Splits string on a regular expression. Optional argument limit is
the maximum number of splits. Not lazy. Returns vector of the splits.
user=> (clojure.string/split "q1w2e3r4t5y6u7i8o9p0" #"\d+") ["q" "w" "e" "r" "t" "y" "u" "i" "o" "p"] user=> (clojure.string/split "q1w2e3r4t5y6u7i8o9p0" #"\d+" 5) ["q" "w" "e" "r" "t5y6u7i8o9p0"]
;; Splits a string on space character and joins
;; the resulting collection with a line feed character
(use '[clojure.string :only (join split)])
user=> (println
(join "\n"
(split "The Quick Brown Fox" #"\s")))
The
Quick
Brown
Fox
nil
(use '[clojure.string :only (split triml)])
;; Splitting on whitespace is a common desire.
user=> (split "Some words to split" #"\s+")
["Some" "words" "to" "split"]
;; By using the pattern #"\s+", we split on all occurrences of one or
;; more consecutive whitespace characters.
user=> (split "Some words with\tother whitespace \n" #"\s+")
["Some" "words" "with" "other" "whitespace"]
;; If you are used to Perl's special behavior of split(' ', $str),
;; where it ignores leading whitespace in the string to be split, this
;; does not quite do it.
user=> (split " Leading whitespace causes empty first string" #"\s+")
["" "Leading" "whitespace" "causes" "empty" "first" "string"]
;; This will do it.
user=> (defn perl-split-on-space [s]
(split (triml s) #"\s+"))
#'user/perl-split-on-space
user=> (perl-split-on-space " This is often what you want ")
["This" "is" "often" "what" "you" "want"]
;; There might be cases where you want this instead.
user=> (split "Some words with\tother whitespace \n" #"\s")
["Some" "" "" "" "words" "" "" "with" "other" "whitespace"]
(use '[clojure.string :only (split)]) ;; Split on every occurrence of : character user=> (split "root:*:0:0:admin:/var/root:/bin/sh" #":") ["root" "*" "0" "0" "admin" "/var/root" "/bin/sh"] ;; Empty strings are returned when two colons appear consecutively in ;; the string to be split. user=> (split "root::0:0::/var/root:/bin/sh" #":") ["root" "" "0" "0" "" "/var/root" "/bin/sh"] ;; Without specifying a limit, any empty strings at the end are ;; omitted. user=> (split "root::0:0:admin:/var/root:" #":") ["root" "" "0" "0" "admin" "/var/root"] user=> (split "root::0:0:admin::" #":") ["root" "" "0" "0" "admin"] ;; If you want all of the fields, even trailing empty ones, use a ;; negative limit. user=> (split "root::0:0:admin:/var/root:" #":" -1) ["root" "" "0" "0" "admin" "/var/root" ""] user=> (split "root::0:0:admin::" #":" -1) ["root" "" "0" "0" "admin" "" ""] ;; Use a positive limit of n to limit the maximum number of strings in ;; the return value to n. If it returns exactly n strings, the last ;; contains everything left over after splitting off the n-1 earlier ;; strings. user=> (split "root::0:0:admin:/var/root:" #":" 2) ["root" ":0:0:admin:/var/root:"] user=> (split "root::0:0:admin:/var/root:" #":" 3) ["root" "" "0:0:admin:/var/root:"] user=> (split "root::0:0:admin:/var/root:" #":" 4) ["root" "" "0" "0:admin:/var/root:"] user=> (split "root::0:0:admin:/var/root:" #":" 15) ["root" "" "0" "0" "admin" "/var/root" ""]
Source
clojure/string.clj:169
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(defn split
"Splits string on a regular expression. Optional argument limit is
the maximum number of splits. Not lazy. Returns vector of the splits."
{:added "1.2"}
([^CharSequence s ^Pattern re]
(LazilyPersistentVector/createOwning (.split re s)))
([ ^CharSequence s ^Pattern re limit]
(LazilyPersistentVector/createOwning (.split re s limit))))
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