user=> (take 5 (cycle ["a" "b"]))
("a" "b" "a" "b" "a")
user=> (take 10 (cycle (range 0 3)))
(0 1 2 0 1 2 0 1 2 0)
MrHus
on Thu, 19 May 2011
user=> (take 5 (cycle ["a" "b"]))
("a" "b" "a" "b" "a")
user=> (take 10 (cycle (range 0 3)))
(0 1 2 0 1 2 0 1 2 0)
zkim
on Sun, 26 Sep 2010
user=> (take 5 (cycle ["a" "b"]))
("a" "b" "a" "b" "a")
nipra
on Wed, 14 Jul 2010
user> (take 5 (cycle ["a" "b"]))
("a" "b" "a" "b" "a")