user=> (map #(%1 %2) (cycle [inc identity]) [1 2 3 4 5 6 7 8 9 10]) (2 2 4 4 6 6 8 8 10 10)
zkim
on Sun, 26 Sep 2010
user=> (map #(%1 %2) (cycle [inc identity]) [1 2 3 4 5 6 7 8 9 10]) (2 2 4 4 6 6 8 8 10 10)
cschreiner
on Thu, 15 Jul 2010
(map #(%1 %2) (cycle [inc identity]) [1 2 3 4 5 6 7 8 9 10]) (2 2 4 4 6 6 8 8 10 10)