user=> (partition-by #(= 3 %) [1 2 3 4 5]) ((1 2) (3) (4 5))
jafingerhut
on Wed, 28 Mar 2012
user=> (partition-by #(= 3 %) [1 2 3 4 5]) ((1 2) (3) (4 5))
wilkes
on Fri, 23 Jul 2010
user=> (partition-by #(= 3 %) [1 2 3 4 5]) ((1 2) (3) (4 5))